Download full version of pro 100 for free at Softonic. PRO100: PRO100 is a powerful 3D interior and furniture design .Q:
Type of address specified by by setArgv() is 0x28, not 0x20?
This is an example of my code.
int main(int argc, char* argv[])
{
setArgv(argc, argv, "0x28");
return 0;
}
I am passing the address 0x28 as my second argument. (This 0x28 is in hexadecimal. That means it is a 4-byte address.)
Then, in the main function, I print out the address as a string. This is the output.
"0x28"
I'm not sure what this "0x28" is referring to. It's not just my computer's OS. I have a friend who has the same OS as me, and he has an identical hard drive. He has the same code, and he gets the same output. So I'm not sure what this 0x28 is.
What is it?
A:
There's nothing to be mysterious about the integer representation of memory addresses. They are the way the computer (typically) stores memory.
This means that the computer will store a value of zero to memory address 0x28 and the byte at this address will be zero.
You are lucky that the value you are using is a valid memory address because if it wasn't you'd get a segmentation fault.
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